TypeScript Interface Required property based on another property

I want to define a function like this:

function someFunctionWithSomeConfigPassedIn(config: SomeConfig) {      }  

SomeConfig interface looks like this:

interface SomeConfig {    type: SomeEnumType;    paramRequiredForType1?: any; // How do I make this required when type is Type1 but optional when type is other type?    paramRequiredForType2?: any; // How do I make this required when type is Type2 but optional when type is other type?    paramRequiredForType3?: any; // How do I make this required when type is Type3 but optional when type is other type?  }  

It's based off an enum:

enum SomeEnumType {    Type1 = 'Type1',    Type2 = 'Type2',    Type3 = 'Type3',  }  

I want to make the additional params required based on SomeEnumType. How can I do that?

Should I just use union type instead?:

interface Type1Config {    type: SomeEnumType.Type1;    paramRequiredForType1: any;  }  interface Type2Config {    type: SomeEnumType.Type2;    paramRequiredForType2: any;  }  interface Type3Config {    type: SomeEnumType.Type3;    paramRequiredForType3: any;  }    function someFunctionWithSomeConfigPassedIn(config: Type1Config | Type2Config | Type3Config) {      }  

https://stackoverflow.com/questions/67048097/typescript-interface-required-property-based-on-another-property April 12, 2021 at 01:23AM