Outputting after a delay on subscribe using rxjs operators

I need to get an output like the following:

computing 1  5  6  7  8    wait 2 seconds    computing 2  5  6  7  8    wait 2 seconds  ...  

but with the following code

from([1,2,3,4]).pipe(      concatMap(n => of(n).pipe(          tap(n => {console.log(`computing ${n}`)}),          concatMap(n => from([5,6,7,8])),          delay(2000)      ))  ).subscribe((val) => {console.log(val)}, () => {}, () => {console.log(`end`)})  

the output will be

computing 1    wait 2 seconds    5  6  7  8  computing 2    wait 2 seconds    5  6  7  8  computing 3  

because the delay will take effect after the innermost flattening and cause next computing x string to be printed right after the value emissions. Instead, I need to get the above example output without getting an initial delay, is it possible?

https://stackoverflow.com/questions/67244714/outputting-after-a-delay-on-subscribe-using-rxjs-operators April 24, 2021 at 11:54PM