Suppose we have a DataFrame like this, only with many, many more index A values:
df = pd.DataFrame([[1,2,1,2], [1,1,2,2], [2,2,1,0], [1,2,1,2], [2,1,1,2] ], columns=['A','B','c1','c2']) df.groupby(['A','B']).sum() ## result c1 c2 A B 1 1 2 2 2 2 4 2 1 1 2 2 1 0 How can I get a data frame that consists of the difference between rows, by the second level of the index, level B? The output here would be
A c1 c2 1 0 -2 2 0 2 Note In my particular use case, I have a lot of column A values, so I can write out the value for A explicitly.
https://stackoverflow.com/questions/67067203/how-to-find-difference-between-rows-in-a-pandas-multiindex-by-level-1 April 13, 2021 at 08:21AM
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