Scala version - 2.11
Ex: case class header(name:String, version:String)
I want to define a configurable case class.
Approach 1: --didn't work
val columnList = "name:String,version:String" case class header(columnList) Approach 2: dynamically create case class on runtime.
How would I go on about doing that? I want to read a list of columns from .config file and be able to represent a case class with the n # of columns.
Any other approaches would be helpful? Thanks.
https://stackoverflow.com/questions/66681149/scala-how-do-define-a-case-class-dynamically March 18, 2021 at 05:00AM
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