Expect:
Select data from my SQL. Foreach to echo data and the button. When the data is null, display the "join" button with onclick function. When the data is "joined", hide the "join"button with onclick function, display the "result" button with onclick function.
Result:
Cannot hide the "join"button with onclick function, display the "result" button with onclick function.
<!DOCTYPE html> <html> <head> </head> <body> <?php $servername = "localhost"; $username = "root"; $password = ""; $dbname = "battle"; try { $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $stmt = $conn->prepare("SELECT * FROM battleRecord Group by id"); $stmt->execute(); $stmt->setFetchMode(PDO::FETCH_ASSOC); foreach ($stmt->fetchAll() as $row) { if ($row['participation'] == 'joined') { $displayJoin = 'none'; $displayResult = 'block'; } else { $displayJoin = 'block'; $displayResult = 'none'; } ?> <tr> <td style='width:150px;border:1px solid black;'> <p><?php echo $row['id']?></p> </td> <td style='width:150px;border:1px solid black;'> <button style="display:<?php echo $displayjoin ?>" id="joinBattle" onclick="joinBattle(<?php echo htmlspecialchars($row['id']) ?>)">joinbattle</button> <button style="display:<?php echo $displayResult ?>" id="checkResult" onclick="checkResult(<?php echo htmlspecialchars($row['result']) ?>)">result</button> </td> </tr> <?PHP } } catch (PDOException $e) { echo "Error: " . $e->getMessage(); } $conn = null; ?> </body> </html> Result and Mysql
https://stackoverflow.com/questions/66575687/how-to-echo-button-with-onclick-function-using-foreach-and-condition-in-php March 11, 2021 at 10:35AM
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