The following is Octave/Matlab code
x=linspace(0,1,100); y=linspace(0,1,100); [X,Y]=meshgrid(x,y); Z=-(X.^2+Y.^2)+1; figure(1) surf(X.^6,Y.^6,Z); shading interp;view([0 90]); axis tight colorbar; What is the equivalent using PyPlot in Julia?
https://stackoverflow.com/questions/66739088/custom-scaling-in-julia-pyplot March 22, 2021 at 08:54AM
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