I have a first table of customer data:
|BillTo |ShipTo_Code|Name |Address |ProductNum |UoM |Price | |:------|-----------|--------|------------------|-----------|----|-------| |101308 |0526 |Store 1 |118 Washington St.| | | | |101308 |0542 |Store 2 |62 Central St. | | | | |101308 |0716 |Store 3 |15 Walnut Rd. | | | | |101308 |0817 |Store 4 |211 Sudbury Rd. | | | |
And I have a second table that has product and pricing data for customers:
|BillTo |ProductNum |UoM |Price | |:------|-----------|----|-------| |101308 |3100121 |CS |2.90 | |101308 |3100697 |CS |2.45 | |101308 |3300072 |CS |67.80 | |101308 |3300075 |CS |5.45 |
I need to insert the pricing data into the customer table so that all 4 products appear for every change in ShipTo_Code. It should end up like this:
|BillTo |ShipTo_Code|Name |Address |ProductNum |UoM |Price | |:------|-----------|--------|------------------|-----------|----|-------| |101308 |0526 |Store 1 |118 Washington St.|3100121 |CS |2.90 | |101308 |0526 |Store 1 |118 Washington St.|3100697 |CS |2.45 | |101308 |0526 |Store 1 |118 Washington St.|3300072 |CS |67.80 | |101308 |0526 |Store 1 |118 Washington St.|3300075 |CS |5.45 | |101308 |0542 |Store 2 |62 Central St. |3100121 |CS |2.90 | |101308 |0542 |Store 2 |62 Central St. |3100697 |CS |2.45 | |101308 |0542 |Store 2 |62 Central St. |3300072 |CS |67.80 | |101308 |0542 |Store 2 |62 Central St. |3300075 |CS |5.45 | |101308 |0716 |Store 3 |15 Walnut Rd. |3100121 |CS |2.90 | |101308 |0716 |Store 3 |15 Walnut Rd. |3100697 |CS |2.45 | |101308 |0716 |Store 3 |15 Walnut Rd. |3300072 |CS |67.80 | |101308 |0716 |Store 3 |15 Walnut Rd. |3300075 |CS |5.45 | etc.
The only match between the 2 tables is the BillTo.
I've spent a lot of time looking at similar questions here, but have not really been able to apply the solutions I've seen in threads so far.
This thread gave me a good start, but it's doing it within the same table.
Any assistance would be very much appreciated.
https://stackoverflow.com/questions/66072560/sql-server-insert-from-second-table-for-every-unique-value-in-first-table-with February 06, 2021 at 08:58AM
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