Update The below code runs now after kernel restart. I'm leaving the question since I didn't see this exact method of converting the plot object into a list and appending.
I want to dynamically create a list of ggplot2::ggplot objects (gg) and pass that list to gridExtra::grid.arrange() to draw them.
However, I'm getting errors when I try (see bottom of code below).
How do I create a list of ggplots and use it in grid.arrange() (or anywhere I want one or more gg objects or grobs)?
I've looked at these posts, but the solutions didn't work.
Here's a simple example with outputs:
# RStudio Version 1.3.1093 # R version 4.0.3 (2020-10-10) # ggplot2 version 3.3.2 # gridExtra version 2.3 library(ggplot2) library(gridExtra) test_fun = function (x) { plt_lst = list() for(col in colnames(x)){ plt = ggplot(data = x, aes(x = x[ , col])) + geom_histogram() plt_lst = append(plt_lst, list(plt)) grid.arrange(plt) # Draws each graph. print(is(plt)) # [1] "gg" print(is(plt[[1]])) # [1] "data.frame" "list" "oldClass" "vector" } return(plt_lst) } df = data.frame(a = rnorm(n = 50), b = rnorm(n = 50)) test_plt_lst = test_fun(df) print(is(test_plt_lst)) # [1] "gg" print(is(test_plt_lst[[1]])) # [1] "data.frame" "list" "oldClass" "vector" # grid.arrange(test_plt_lst) # # Error in gList(list(data = list(a = c(1.14459276559037, 2.33485713757935, : only 'grobs' allowed in "gList" # Works do.call(grid.arrange, test_plt_lst) # The following error no longer appearing. # Error in `$<-.data.frame`(`*tmp*`, "wrapvp", value = list(x = 0.5, y = 0.5, : replacement has 17 rows, data has 50 https://stackoverflow.com/questions/65588968/how-to-create-a-list-of-ggplot-objects-that-grid-arrange-will-accept-and-draw-in January 06, 2021 at 09:30AM
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