I'm trying to detect the parentheses on string for example: foo(bar)baz(blim)
to and reverse the content inside of the parentheses but I'm getting out of bounce range on my implementation:
func reverseInParentheses(inputString: String) -> String { var tmpStr = inputString var done = false while !done { if let lastIndexOfChar = tmpStr.lastIndex(of: "(") { let startIndex = tmpStr.index(lastIndexOfChar, offsetBy:1) if let index = tmpStr.firstIndex(of: ")") { let range = startIndex..<index let strToVerse = String(tmpStr[range]) let reversedStr = reverseStr(str: strToVerse) tmpStr = tmpStr.replacingOccurrences(of: "(" + strToVerse + ")", with: reversedStr) } } else { done = true } } return tmpStr }
how can I get the tmpStr.firstIndex(of: ")")
after the startIndex
any of you knows how can do that?
I'll really appreciate your help
https://stackoverflow.com/questions/65402215/swift-string-firstindex-after-character December 22, 2020 at 09:38AM
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